Topic 3: Three Dimensional Figures - Basic Mathematics Form Four

Topic 3: Three Dimensional Figures – Basic Mathematics Form Four

Basic Mathematics For Form Four Full Notes, LINEAR PROGRAMMING. Linear programming – is a branch of mathematics which deals with either minimizing the cost or maximizing the profit. It gives the best way of utilizing the scarce resources available. It is so called because it only involves equations and inequalities which are linear. Simultaneous Equation. One of the methods used in solving linear simultaneous equations is a graphical method. Two linear simultaneous equations in two unknowns can be graphically solved by passing through the following procedures. Draw the two lines which represent the two equations on the xy – plane this is done by deter mining at least two points through which each line passes, the intercept are commonly used Determine the point of intersection of the two lines. This point of intersection is the solution to the system of equations. FACT: If two straight lines are not parallel then they meet at only one point: In case the lines do not meet, there is no solution to the corresponding system of simultaneous equations. Example 1 Graphically solve the following system of simultaneous equations. Example 2 Find the solution to the following system of simultaneous equations by graphical method. Solving Simultaneous Equations Graphically Solve simultaneous equations graphically Example 3 Solve the following simultaneous equations graphically and check your solution by a non-graphical method: Example 4 Find the solution to the following system of simultaneous equations by graphical method. Exercise 1 Find the solution to the following systems of simultaneous equations graphically. Try: Ali paid 34 shillings for 10 oranges and 35 mangoes. Moshi went to the same market and paid 24 shillings for 16 oranges and 18 mangoes. What was the price for a mango and for an orange? Inequalities Forming Linear Inequalities in Two Unknowns from Word Problems Form linear inequalities in two unknowns from word problems Linear inequalities Normally any straight line drawn on xy – plane separates it into two disjoint sets. These sets are called half – planes Consider the equation y = 5 drawn on the xy plane as shown below. From the figure above, all points above the line, that is all points in the half plane A which is above the line satisfy the relation y>5 and those lying in the half plane B which is below the given line, satisfy the relation y< 5. Shading of Regions In linear programming usually the region of interest is left clear that is we shade unwanted region(s). NB: When shading the half planes we consider the inequalities as the equations but dotted lines are used for the relations with > or < signs and normal lines are used for those with ≥ or ≤ signs. Consider the inequalities x>0, y>0 and 2x + 3y >12 represented on the xy-plane In this case we draw the line x=0, y= 0 and 2x+3y=12 but the point about the inequality signs for each equation must be considered. From the figure above, the clear region satisfy all the inequalitiesx>0, y>0 and 2x + 3y >12, these three lines are the boundaries of the region. The Solution Set of Simultaneous Linear Inequalities Graphically Find the solution set of simultaneous linear inequalities graphically Example 5 Draw and show the half plane represented by 8x + 2y ≥16 Feasible Region Definition: In the xy plane the region that satisfies all the given inequalities is called the feasible region (F.R) Example 6 Indicate the feasible region for the inequalities 2x+3y ≥ 12 and y-x ≤ 2. Determine the solution set of the simultaneous inequalities y + x ≥3 and x-2y ≤ 9. Example 7 Fatuma was given 30 shillings to buy oranges and mangoes. An orange costs 2 shillings while a mango costs 3 shillings. If the number of oranges bought is at least twice the number of mangoes, show graphically the feasible region representing the number of ranges and mangoes she bought, assuming that no fraction of oranges and mangoes are sold at the market. Solution:- Let x be the number of oranges she bought and y the number of mangoes she bought. Now the cost of x and y together is 2x + 3y shillings which must not exceed 30 shillings. Inequalities: 2x + 3y ≤30 ……… (i) and x≥2y …………….. (ii), Also because there is no negative oranges or mangoes that can be bought, then x≥ and y≥0 ……….. (iii) Now the line 2x + 3y ≤30 is the line passing through (0, 10) and (15,0) and the line x≥2y or x – 2y ≥ 0 is the line which passes through (0,0) and (2,1). Exercise 2 For practice. Draw the graph of the equation 2x – y = 7 and show which half plane is represented by 2x – y >7 and the one represented by 2x – y 3 – x on the same axes and indicate the feasible region. A post office has to transport 870 parcels using a lorry, The Objective Function An Objective Function from Word Problems Form an objective function from word problems Linear programming components Any linear programming problem has the following: Objective Alternative course (s) of action which will achieve the objective. The available resources which are in limited supply. The objective and its limitations should be able to be expressed as either linear mathematical equations or linear inequalities. Therefore linear programming aims at finding the best use of the available resources. Programmingis the use of mathematical techniques in order to get the best possible solution to the problem Steps to be followed in solving linear programming problems; Read carefully the problem, if possible do it several times. Use the variables like x and y to represent the resources of interest. Summarize the problem by putting it in mathematical form using the variables let in step (b) above. In this step you need to formulate the objective function and inequalities or constraints. Plot the constraints on a graph From your graph, identify the corner points. Use the objective function to test each corner point to find out which one gives the optimum solution. Make conclusion after finding or identifying the optimum point among the corner points. Maximum and Minimum Values Corner Points on the Feasible Region Locate corner points on the feasible region Example 8 A student has 1200 shillings to spend on exercise books. At the school shop an exercise book costs 80shillings, and at a stationery store it costs 120 shillings. The school shop has only 6 exercise books left and the student wants to obtain the greatest number of exercise books possible using the money he has. How many exercise books will the student buy from each site? Therefore the student will buy 6 exercise books from each site. Example 9 A nutritionist prescribes a special diet for patients containing the following number of Units of vitamins A and B per kg, of two types of food f1 and f2 If the daily minimum in take required is 120 Units of A and 70 units of B, what is the least total mass of food a patient must have so as to have enough of these vitamins? Solution: Let x be the number of kg(s) of F1 that patient gets daily and y be the number of kg(s) of F2 to be taken by the patient daily. Objective function: F (x, y) = (x + y) minimum f (C) = 10 + 0 = 10 So f (B) = 6.8 is the minimum Therefore the least total mass of food the patient must have is 6.8 kilograms The Minimum and Maximum Values using the Objective Functio Find the minimum and maximum values using the objective function Example 10 A farmer wants to plant coffee and potatoes. Coffee needs 3 men per hectare while potatoes need also 3 men per hectare. He has 48 hired laborers available. To maintain a hectare of coffee he needs 250 shillings while a hectare of potatoes costs him 100 shillings. . Find the greatest possible land he can sow if he is prepared to use 25,000 shillings. Solution: Let x be the number of hectares of coffee to be planted and y be the number of hectares of potatoes to be planted. Objective function: f (x, y) = (x, + y) maximum 3x + 3y ≤ 48 or x + y ≤16 ………….(i) 250x + 100y≤ 25,000 Or 5x + 2y ≤ 500………(ii) x ≥ 0 ……………………(iii) y≥ 0 ……………………(iv) Using the objective function f (x, y) = (x + y) maximum, f (A) = (0 + 250) = 250 f (B) = (0+16) = 16 f (C) = (16+0) = 16 f(D) = (100+0)= 100 (maximum) Therefore the greatest possible area to be planted is 250 hectors of potatoes. NB: In most cases L.P problems must involve non-negativity constraints (inequalities) that are x ≥ 0 and y ≥ 0. This is due to the fact that in daily practice there is no use of negative quantities. Example 11 A technical school is planning to buy two types of machines. A lather machine needs 3m2 of floor space and a drill machine needs 2m2 of floor space. The total space available is 30m2. The cost of one lather machine is 25,000 shillings and that of drill machine is 30,000 shillings. The school can spend not more than 300,000 shillings, what is the greatest number of machines the school can buy? Solution: Let x be the number of Lather machines and y be the number of drill machines to be bought Objective function: f(x, y) = (x + y) max Inequalities: 3x + 2y ≤ 30.. ………………….(i) 25,000x + 30,000y ≤300,000 Or 5x + 6y ≤ 60……………………..(ii) x ≥ 0 ……………………………….(iii) y ≥ 0…………………… ………….(iv) Since the incomplete machine can’t work, then B = (8, 3) or (7, 4).That is approximating values of x and y to the possible integers without affecting the given inequalities or conditions. Now by using the objective function, f (A) = 0 + 10 = 10 f(B) = 7 + 4 0r f (B) = 8 + 3 = 11 f (C) = 10 + 0 = 10 f (D) = 0 + ) = 0 So f (B) gives the maximum number of machines which is 11. Therefore the greatest number of machines that can be bought by the school is 11 machines. Exercise 3 1. Show on a graph the feasible region for which the restrictions are: y ≤ 2x, x≥ 6, y≥2 and 2x + 3y ≤30 From the graph at which point does: y – x take a maximum value? x + y take a maximum value? y – x take a maximum value? 2. With only 20,000 shillings to spend on fish, John had the choice of buying two types of fish. The price of a single fish type 1 was 2,500shillings and each fish of type 2 was sold at 2,000 shillings. He wanted to buy at least four of type 1. What is the greatest number of fish did John buy? How many of each type could he buy? 3. How many corner points does the feasible region restricted by the inequalities? x≥0, y ≥ 0, 3x + 2y ≤ 18 and 2x + 4y ≤16 have? Which corner point maximizes the objective function f (x, y) = 2x + 5y?, Matrices and Transformation, Topic 6: Vectors - Basic Mathematics Form Four, Trigonometry, Probability, Three Dimensional Figures, Area and Perimeter, Coordinate Geometry, Statistics, Similarity

Topic 3: Three Dimensional Figures – Basic Mathematics Form Four

Three Dimensional Figures

Sometimes before you make any purchases you may want to know for example, how much cloth you need to make a pillow cover. What about a cover for your mattress or sofa cushion? How much oil paint do you need to paint your drinking water tank?

What about the amount of cloth for the pocket covers of your radio, curtain, suit, gown, trousers, set of table clothes, etc.

Answers to such questions and of the kind leads you to think more carefully about the size of the surfaces (faces) to be covered or coated on the bodies at work. Perhaps you need to take some measurements on the surfaces.

The knowledge of the surface areas of such bodies will enable you to choose or purchases the required amount without unnecessary wastage so as to minimize purchases costs too.

Three Dimensional Figures

Classify three dimensional figures

Three‐dimensional objects
are the solid shapes you see every day, like boxes, balls, coffee cups, and cans.

It is called three-dimensional or 3D because there are three dimensions: width, depth and height.

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-The following table shows examples of some common three dimensional figures

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The Characteristics of Each Class

List the characteristics of each class

Here are some helpful vocabulary terms for solids:

Base: Is the bottom surface of a solid object.

Edge: Is the intersection of two faces on a solid object. This is a line.

Face: Is a flat side of a 3‐dimensional object.

Prism: Is a solid object with two congruent and parallel faces.

Pyramid: Is a solid object with a polygon for a base and triangles for sides.

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Construction of Three Dimensional Figures

Three Dimensional Figures

Construct three dimensional figures

When drawing a three dimensional object it is important to show that it is not a drawing of a flat object. Are usually drawn on a two dimensional plane by making oblique drawings under certain rules as follows:

  1. Paralled lines are drawn parallel.
  2. Vertical lines are drawn up and down the page.
  3. Hidden edges are drawn dotted.
  4. Construction lines to guide the eyes are drawn thinly.

Activity 1

Construct three dimensional figures

Sketching Three Dimensional Figures

Three Dimensional Figures

Sketch three dimensional figures

There are several ways of doing the drawing that corresponds to looking at the cube from different angles. The figure shows two ways of doing it.

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Properties of Three Dimensional Figures

Identify properties of three dimensional figures

Three dimensional shapes have many attributes such as faces, edges andvertices. The flat surfaces of the 3D shapes are called the faces. The line segment where two faces meet is called an edge. Avertexis a point where 3 edges meet.

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The Angle Between a Line and a Plane

Find the angle between a line and a plane

In finding the angle between the line and a plane in a three dimensional geometry, we use the right angled triangle. Joining the line to define the angle between the line and the plane that provides the least possible angle. Also, projection of one line to another on the plane is mostly used.

Example 1

For the pyramid VABCD with VA=VB=VC=VD=5m, and ABCD a square of side 4cm; find the angle between VA and ABCD.

Solution

Calculated by dropping a perpendicular from V to ABCD. This meets ABCD at X, the centre of the square.

So the projection of VA on ABCD is AX. AC= square root of (AB2 +BC2) =square of 42+42 =square root of 32. AX =1/2square root of32. cos (1/2square root 32)/5=0.5657, so VAX is 55.6.

The Angle Between Two Planes

Calculate the angle between two planes

There are infinite possible lines that could be drawn on planes, making different angles with each other. The angle between planes is the angle between lines within those planes, Must be the lines which are at the middle of the plane for non rectangular planes and any other lines for rectangular planes. Then Right angled triangles are used to find the angles between those planes.

Example 2

Determine the angle between the following planes:

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Surface Area of Three Dimensional Objects

The Formulae for Calculating the Surface Area of Prisms, Cylinder and Pyramids and Cone

Derive the formulae for calculating the surface area of prisms, cylinder and pyramids and cone

Surface Area of a Right Circular Cone

A right circular cone is a cone whose vertex is vertically above the centre of the base of the cone.

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Area of circular base =Πr2 (it is an area of a circle)

Therefore the total surface area of a right circular cone =Πr2 +Πrs = Πr (r + s)

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Example 3

Find the total surface of right circular cone whose slant light is 10cm and whose base radius is 8cm.Use Πr(r +s)

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Example 4

Find the total surface area of a cone with diameter 8m and slant height of 10m. Use Π= 3.14

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Surface Area of A Right Cylinder

If you want to know the amount of the covering the surface of a blue band margarine can, then you are finding the surface area of a right cylinder. Total surface area of the can is the sum of the areas of the top and bottom. Circular surfaces plus the area of the curved surface,

Now, consider a right cylinder of radius r and height h.

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If the cylinder is opened up, the curved surface flattens out to form a rectangle. The length of the rectangle is 2Πr(the circumference of the circular base) and the width is h (the height of the cylinder).

Total surface area of cylinder:

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Example 5

Find the total surface area of a cylinder with radius of 3m and height of 10m. Use Π= 3.14

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Surface Area of a Right Pyramid

A right pyramid is one in which the slant edges joining the vertex to the corner of the base are equal

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Example 6

A right rectangular pyramid is such that the rectangle is 12cm by 8cm and each slant edge is 12cm. Find the total surface area of the pyramid.

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Surface Area of a Right Prism

A full brick or concrete block is an example of a right rectangular prism

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A right prism is a prism in which each of the vertical edges is perpendicular to the plane of the base.

The figure above shows a rectangular right prism in which there are 6 faces though only three of them can be seen easily.

Surface Area = Total or sum of the areas of each face.

Generally for any right prism,

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Example 7

The height of a right prism is 4cm and the perimeter of its base is 30cm. Find the area of its lateral surface.

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Example 8

Find the total surface area of a rectangular prism 12 by 8 by 6 cm high.

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The Formulae to Calculate the Surface Area of Spheres

Apply the formulae to calculate the surface area of spheres

Surface Area of a Sphere

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The figure above shows a sphere (ball) with radius “r”

The surface area of a sphere is four times the area of circle with the same radius. The area of a circle is Πr2. Hence, the surface area of sphere is equal to 4Πr2.

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Example 9

Find the surface area of a sphere of radius 5cm. (Π= 3.14)

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Example 10

Find the surface area of a tennis ball, given that its radius is 3.3cm. UseΠ= 3.14 Express your answer to the nearest tenth.

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Exercise 1

Do the exercise to check your understanding. Use π= 3.14 throughout the exercise.

1.The altitude of a rectangular prism is 4cm and the width and lengths of its base are 2cm and 3cm respectively calculate the total surface area of the prism.

2. The following diagram shows a cylinder of diameter 20 units and height 9 units. What is its curved surface area?

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Volume of Three Dimensional Objects

The Formulae for Calculating Volume of Prisms, Cylinders and Pyramids

Derive the formulae for calculating volume of prisms, cylinders and pyramids

VOLUMS OF SOME THREE – DIMENSIONAL FIGURES

We have seen some formulas for calculating the surface areas of some three dimensional figures.

Let us see as well formulas for calculating the volumes of such figures.

-The amount of space that is enclosed by a space figure is called the volume.

The Volume is measured in cubic units, cubic meters (m3), Cubic centimeters (cm3) etc.

When we find (calculate) the volume of a space figure or solid, we are finding the number of

cubic units enclosed by the given spaces figure.

(a) Volume of a Right Prism

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The figure above shows a right rectangular prism. Let h be height, w width and ɭ the length of the prism.

Then the Volume of the prism is given by: V = Base area x height= ɭ×W×h

Generally, volume of any right prism is equal to the product of the area of the base and the height V = Base area x height.

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(b) Volume of a Right Cylinder

Consider a right circular cylinder with radius” r “and height h as shown below.

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The volume of a right circular cylinder is equal to the product of the area of the base and the height.

If V is volume, A is area of the base and h is the height,

Then Volume = Area of base x height

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(c) Volume of a Pyramid

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Generally, the volume of a pyramid is one – third the product of its altitude (height) and its base area.

If h is the perpendicular distance from the vertex of the pyramid to its base then,

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(d)Volume of a Cone

Consider a cone of radius “r” and altitude h as shown below.

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(e) Volume of a Sphere

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The figure above shows a sphere of radius r, if the sphere can be put inside a cylinder of the same radius” r”, then the height h = 2r.

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The Formulae to Calculate the Volume of Cylinders, Pyramids and Cones

Apply the formulae to calculate the volume of cylinders, pyramids and cones

Example 11

Find the volume of the prism shown below, given that the dimensions are in meters (m)

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Example 12

Calculate the volume of a rectangular prism whose base is 8cm by 5cm and whose height is 10cm.

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Example 13

Calculate the radius of a right circular cylinder of volume 1570m3 and height 20m. Use π=3.14

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Example 14

A pipe made of metal 1cm thick, has an external (outside) radius of 6cm. Find the volume of metal used in making 4m of pipe. Use π=3.14

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Example 15

Find the volume of a pyramid with rectangular base with length 6m and width 4m if the height of the pyramid is 10m.

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Example 16

Calculate the volume of a square pyramid whose altitude is 10cm and length of side of base is 6cm.

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Example 17

Calculate the volume of a cone having base radius 10cm and altitude 12 cm Use π=3.14

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Example 18

Find the volume of a sphere whose radius is 10cm. (Take π= 3.14).

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Example 19

The volume of a spherical tank is 268m3. Calculate the radius of the tank. (π= 3.14)

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Example 20

Find the volume of rubber in a hollow spherical ball with inner diameter 14cm and outer diameter 16cm. (Take π = 3.14)

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Exercise 2

Answer the following questions and (use π = 3.14)

1. What is the volume of a right prism whose base is a regular hexagon ( n = 6) with a side of the base 4cm long and the height of the prism.

2. Find the volume of a cylinder whose diameter is 28cm and whose height is 12cm.

3. Find the volume of a square pyramid whose height is 24cm and slant edge 25cm each.

4. The slant height of a cone is 20cm and the radius of its base is 12cm. Find its volume in terms of π.

5. The volume of a sphere is 827cm3. Find its radius.

6. A cylinder and sphere have the same volume. If the radius of the sphere is 5cm and radius of the cylinder is 3cm, Calculate height of the cylinder.

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8.The diagram shows a barn. What is the volume of the barn? (The length of the hypotenuse in the right triangle is rounded to the nearest foot.)

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9.What is the volume of this prism?

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The diagram shows a prism whose cross-section is a right triangle. What is the volume of the prism?

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Summary of the topic

Here are the important formulas you have covered under the section on surface areas summarized.

Surface area of:

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You can now have a summary of the important formulas for calculating volume of some three dimensional figures as follows: –

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