Topic 5: Trigonometry - Basic Mathematics Form Four

Topic 5: Trigonometry – Basic Mathematics Form Four

Basic Mathematics For Form Four Full Notes, LINEAR PROGRAMMING. Linear programming – is a branch of mathematics which deals with either minimizing the cost or maximizing the profit. It gives the best way of utilizing the scarce resources available. It is so called because it only involves equations and inequalities which are linear. Simultaneous Equation. One of the methods used in solving linear simultaneous equations is a graphical method. Two linear simultaneous equations in two unknowns can be graphically solved by passing through the following procedures. Draw the two lines which represent the two equations on the xy – plane this is done by deter mining at least two points through which each line passes, the intercept are commonly used Determine the point of intersection of the two lines. This point of intersection is the solution to the system of equations. FACT: If two straight lines are not parallel then they meet at only one point: In case the lines do not meet, there is no solution to the corresponding system of simultaneous equations. Example 1 Graphically solve the following system of simultaneous equations. Example 2 Find the solution to the following system of simultaneous equations by graphical method. Solving Simultaneous Equations Graphically Solve simultaneous equations graphically Example 3 Solve the following simultaneous equations graphically and check your solution by a non-graphical method: Example 4 Find the solution to the following system of simultaneous equations by graphical method. Exercise 1 Find the solution to the following systems of simultaneous equations graphically. Try: Ali paid 34 shillings for 10 oranges and 35 mangoes. Moshi went to the same market and paid 24 shillings for 16 oranges and 18 mangoes. What was the price for a mango and for an orange? Inequalities Forming Linear Inequalities in Two Unknowns from Word Problems Form linear inequalities in two unknowns from word problems Linear inequalities Normally any straight line drawn on xy – plane separates it into two disjoint sets. These sets are called half – planes Consider the equation y = 5 drawn on the xy plane as shown below. From the figure above, all points above the line, that is all points in the half plane A which is above the line satisfy the relation y>5 and those lying in the half plane B which is below the given line, satisfy the relation y< 5. Shading of Regions In linear programming usually the region of interest is left clear that is we shade unwanted region(s). NB: When shading the half planes we consider the inequalities as the equations but dotted lines are used for the relations with > or < signs and normal lines are used for those with ≥ or ≤ signs. Consider the inequalities x>0, y>0 and 2x + 3y >12 represented on the xy-plane In this case we draw the line x=0, y= 0 and 2x+3y=12 but the point about the inequality signs for each equation must be considered. From the figure above, the clear region satisfy all the inequalitiesx>0, y>0 and 2x + 3y >12, these three lines are the boundaries of the region. The Solution Set of Simultaneous Linear Inequalities Graphically Find the solution set of simultaneous linear inequalities graphically Example 5 Draw and show the half plane represented by 8x + 2y ≥16 Feasible Region Definition: In the xy plane the region that satisfies all the given inequalities is called the feasible region (F.R) Example 6 Indicate the feasible region for the inequalities 2x+3y ≥ 12 and y-x ≤ 2. Determine the solution set of the simultaneous inequalities y + x ≥3 and x-2y ≤ 9. Example 7 Fatuma was given 30 shillings to buy oranges and mangoes. An orange costs 2 shillings while a mango costs 3 shillings. If the number of oranges bought is at least twice the number of mangoes, show graphically the feasible region representing the number of ranges and mangoes she bought, assuming that no fraction of oranges and mangoes are sold at the market. Solution:- Let x be the number of oranges she bought and y the number of mangoes she bought. Now the cost of x and y together is 2x + 3y shillings which must not exceed 30 shillings. Inequalities: 2x + 3y ≤30 ……… (i) and x≥2y …………….. (ii), Also because there is no negative oranges or mangoes that can be bought, then x≥ and y≥0 ……….. (iii) Now the line 2x + 3y ≤30 is the line passing through (0, 10) and (15,0) and the line x≥2y or x – 2y ≥ 0 is the line which passes through (0,0) and (2,1). Exercise 2 For practice. Draw the graph of the equation 2x – y = 7 and show which half plane is represented by 2x – y >7 and the one represented by 2x – y 3 – x on the same axes and indicate the feasible region. A post office has to transport 870 parcels using a lorry, The Objective Function An Objective Function from Word Problems Form an objective function from word problems Linear programming components Any linear programming problem has the following: Objective Alternative course (s) of action which will achieve the objective. The available resources which are in limited supply. The objective and its limitations should be able to be expressed as either linear mathematical equations or linear inequalities. Therefore linear programming aims at finding the best use of the available resources. Programmingis the use of mathematical techniques in order to get the best possible solution to the problem Steps to be followed in solving linear programming problems; Read carefully the problem, if possible do it several times. Use the variables like x and y to represent the resources of interest. Summarize the problem by putting it in mathematical form using the variables let in step (b) above. In this step you need to formulate the objective function and inequalities or constraints. Plot the constraints on a graph From your graph, identify the corner points. Use the objective function to test each corner point to find out which one gives the optimum solution. Make conclusion after finding or identifying the optimum point among the corner points. Maximum and Minimum Values Corner Points on the Feasible Region Locate corner points on the feasible region Example 8 A student has 1200 shillings to spend on exercise books. At the school shop an exercise book costs 80shillings, and at a stationery store it costs 120 shillings. The school shop has only 6 exercise books left and the student wants to obtain the greatest number of exercise books possible using the money he has. How many exercise books will the student buy from each site? Therefore the student will buy 6 exercise books from each site. Example 9 A nutritionist prescribes a special diet for patients containing the following number of Units of vitamins A and B per kg, of two types of food f1 and f2 If the daily minimum in take required is 120 Units of A and 70 units of B, what is the least total mass of food a patient must have so as to have enough of these vitamins? Solution: Let x be the number of kg(s) of F1 that patient gets daily and y be the number of kg(s) of F2 to be taken by the patient daily. Objective function: F (x, y) = (x + y) minimum f (C) = 10 + 0 = 10 So f (B) = 6.8 is the minimum Therefore the least total mass of food the patient must have is 6.8 kilograms The Minimum and Maximum Values using the Objective Functio Find the minimum and maximum values using the objective function Example 10 A farmer wants to plant coffee and potatoes. Coffee needs 3 men per hectare while potatoes need also 3 men per hectare. He has 48 hired laborers available. To maintain a hectare of coffee he needs 250 shillings while a hectare of potatoes costs him 100 shillings. . Find the greatest possible land he can sow if he is prepared to use 25,000 shillings. Solution: Let x be the number of hectares of coffee to be planted and y be the number of hectares of potatoes to be planted. Objective function: f (x, y) = (x, + y) maximum 3x + 3y ≤ 48 or x + y ≤16 ………….(i) 250x + 100y≤ 25,000 Or 5x + 2y ≤ 500………(ii) x ≥ 0 ……………………(iii) y≥ 0 ……………………(iv) Using the objective function f (x, y) = (x + y) maximum, f (A) = (0 + 250) = 250 f (B) = (0+16) = 16 f (C) = (16+0) = 16 f(D) = (100+0)= 100 (maximum) Therefore the greatest possible area to be planted is 250 hectors of potatoes. NB: In most cases L.P problems must involve non-negativity constraints (inequalities) that are x ≥ 0 and y ≥ 0. This is due to the fact that in daily practice there is no use of negative quantities. Example 11 A technical school is planning to buy two types of machines. A lather machine needs 3m2 of floor space and a drill machine needs 2m2 of floor space. The total space available is 30m2. The cost of one lather machine is 25,000 shillings and that of drill machine is 30,000 shillings. The school can spend not more than 300,000 shillings, what is the greatest number of machines the school can buy? Solution: Let x be the number of Lather machines and y be the number of drill machines to be bought Objective function: f(x, y) = (x + y) max Inequalities: 3x + 2y ≤ 30.. ………………….(i) 25,000x + 30,000y ≤300,000 Or 5x + 6y ≤ 60……………………..(ii) x ≥ 0 ……………………………….(iii) y ≥ 0…………………… ………….(iv) Since the incomplete machine can’t work, then B = (8, 3) or (7, 4).That is approximating values of x and y to the possible integers without affecting the given inequalities or conditions. Now by using the objective function, f (A) = 0 + 10 = 10 f(B) = 7 + 4 0r f (B) = 8 + 3 = 11 f (C) = 10 + 0 = 10 f (D) = 0 + ) = 0 So f (B) gives the maximum number of machines which is 11. Therefore the greatest number of machines that can be bought by the school is 11 machines. Exercise 3 1. Show on a graph the feasible region for which the restrictions are: y ≤ 2x, x≥ 6, y≥2 and 2x + 3y ≤30 From the graph at which point does: y – x take a maximum value? x + y take a maximum value? y – x take a maximum value? 2. With only 20,000 shillings to spend on fish, John had the choice of buying two types of fish. The price of a single fish type 1 was 2,500shillings and each fish of type 2 was sold at 2,000 shillings. He wanted to buy at least four of type 1. What is the greatest number of fish did John buy? How many of each type could he buy? 3. How many corner points does the feasible region restricted by the inequalities? x≥0, y ≥ 0, 3x + 2y ≤ 18 and 2x + 4y ≤16 have? Which corner point maximizes the objective function f (x, y) = 2x + 5y?, Matrices and Transformation, Topic 6: Vectors - Basic Mathematics Form Four, Trigonometry, Probability, Three Dimensional Figures, Area and Perimeter, Coordinate Geometry, Statistics, Similarity

Topic 5: Trigonometry – Basic Mathematics Form Four

Trigonometric Ratios

The Sine, Cosine and Tangent of an Angle Measured in the Clockwise and Anticlockwise Directions

Determine the sine, cosine and tangent of an angle measured in the clockwise and anticlockwise directions

The basic three trigonometrical ratios are sine, cosine and tangent which are written in short as Sin, Cos, and tan respectively.

Consider the following right angled triangle.

040523 1538 TOPIC5TRIGO1

Also we can define the above triangle ratios by using a unit Circle centered at the origin.

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If θis an obtuse angle (900<θ<1800) then the trigonometrical ratios are the same as the trigonometrical ratio of 1800-θ

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If θis a reflex angle (1800< θ<2700) then the trigonometrical ratios are the same as that of θ- 1800

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If θis a reflex angle (2700< θ< 3600), then the trigonometrical ratios are the same as that of 3600 -θ

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We have seen that trigonometrical ratios are positive or negative depending on the size of the angle and the quadrant in which it is found.

The result can be summarized by using the following diagram.

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Trigonometric Ratios to Solve Problems in Daily Life

Apply trigonometric ratios to solve problems in daily life

Example 1

Write the signs of the following ratios

  1. Sin 1700
  2. Cos 2400
  3. Tan 3100
  4. sin 300

Solution

a)Sin 1700

Since 1700 is in the second quadrant, then Sin 1700 = Sin (1800-1700) = Sin 100

∴Sin 1700 = Sin 100

b) Cos 2400 = -Cos (2400-1800)= -Cos 600

Therefore Cos 2400= -Cos 600

c) Tan 3100 = -Tan (3600-3100) = – Tan 500

Therefore Tan 3100= -Tan 500

d) Sin 3000= -sin (3600-3000) = -sin 600

Therefore sin 3000= – Sin 600

Relationship between Trigonometrical ratios

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The above relationship shows that the Sine of angle is equal to the cosine of its complement.

Also from the triangle ABC above

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Again using the ΔABC

b2 = a2+c2 (Pythagoras theorem)

And

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Example 2

Given thatA is an acute angle and Cos A= 0.8, find

  1. Sin A
  2. tan A.

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Example 3

If A and B are complementary angles,

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Solution

If A and B are complementary angle

Then Sin A = Cos B and Sin B = Cos A

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Example 4

Given that θand βare acute angles such that θ+ β= 900 and Sinθ= 0.6, find tanβ

Solution

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Exercise 1

For practice

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Sine and Cosine Functions

Sines and Cosines of Angles 0 Such That -720°≤ᶿ≥ 720°

Find sines and cosines of angles 0 such that -720°≤ᶿ≥ 720°

Positive and Negative angles

An angle can be either positive or negative.

Definition:

Positive angle: is an angle measures in anticlockwise direction from the positive X- axis

Negative angle: is an angle measured in clockwise direction from the positive X-axis

040523 1538 TOPIC5TRIGO19

Facts:

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  1. From the above figure if is a positive angle then the corresponding negative angle to is (- 3600) or (+ – 3600)
  2. .If is a negative angle, its corresponding positive angle is (360+)

Example 5

Find thecorresponding negative angle to the angle θif ;

  1. θ= 580
  2. θ= 2450

040523 1538 TOPIC5TRIGO21

Example 6

What is the positive angle corresponding to – 46°?

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SPECIAL ANGLES

The angles included in this group are 00, 300, 450, 600, 900, 1800, 2700, and 3600

Because the angle 00, 900, 1800, 2700, and 3600, lie on the axes then theirtrigonometrical ratios are summarized in the following table.

040523 1538 TOPIC5TRIGO23

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The ∆ ABC is an equilateral triangle of side 2 units

040523 1538 TOPIC5TRIGO25

For the angle 450 consider the following triangle

040523 1538 TOPIC5TRIGO26

The following table summarizes the Cosine, Sine, and tangent of the angle 300 , 450 and 600

040523 1538 TOPIC5TRIGO27

NB: The following figure is helpful to remember the trigonometrical ratios of special angles from 0°to 90°

040523 1538 TOPIC5TRIGO28

If we need the sines of the above given angles for examples, we only need to take the square root of the number below the given angle and then the result is divided by 2.

040523 1538 TOPIC5TRIGO29

Example 7

Find the sine,cosine and tangents of each of the following angles

  1. -1350
  2. 1200
  3. 3300

040523 1538 TOPIC5TRIGO30

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Example 8

Find the value of θif Cos θ= -½ and θ≤ θ≤ 360°

Solution

Since Cos θis – (ve), then θlies in either the second or third quadrants,

Now – Cos (180 –θ= – Cos (θ+1800) = -½= -Cos600

So θ= 1800-600 = 1200 or θ= 1800 + 600 = 2400

θ= 1200 0r θ=2400

Example 9

Consider below

040523 1538 TOPIC5TRIGO32

Exercise 2

Solve the Following.

040523 1538 TOPIC5TRIGO33

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The Graphs of Sine and Cosine

Draw the graphs of sine and cosine

Consider the following table of value for y=sinθ where θranges from – 360°to 360°

040523 1538 TOPIC5TRIGO35

For cosine consider the following table of values

040523 1538 TOPIC5TRIGO36

From the graphs for the two functions a reader can notice that sinθand cosθboth lie in the interval -1 and 1 inclusively, that is -1≤sinθ1 and -1≤cosθ≤1 for all values of θ.

The graph of y= tanθis left for the reader as an exercise

NB: -∞≤ tanθ≤∞the symbol ∞means infinite

Also you can observe that both Sinθnd cosθrepeat themselves at the interval of

360°, which means sinθ= sin(θ+360) = sin(θ+2×3600) etc

and Cosθ=(Cosθ+3600)= Cos(θ+2×3600)

Each of these functions is called a period function with a period 3600

1. Usingtrigonometrical graphs in the interval -3600≤θ≤3600

Find θsuch that

  1. Sin= 0.4
  2. Cos= 0.9

solution

040523 1538 TOPIC5TRIGO37

Example 10

Use the graph of sinθto find the value ofθif

4Sinθ= -1.8 and -3600 ≤θ≤3600

Solution

4Sinθ= -1.8

Sinθ= -1.8÷4 = -0.45

Sinθ= -0.45

So θ= -1530, -270, 2070, 3330

The graphs of sine and cosine functions

Interpret the graphs of sine and cosine functions

Example 11

Use thetrigonometrical function graphs for sine and cosine to find the value of

  1. Sin (-400)
  2. Cos (-400)

Solution

  1. Sin (-400)= – 0.64
  2. Cos (-400)= 0.76

Sine and Cosine Rules

The Sine and Cosine Rules

Derive the sine and cosine rules

Consider the triangle ABC drawn on a coordinate plane

040523 1538 TOPIC5TRIGO38

From the figure above the coordinates of A, B and C are (0, 0), (c, 0) and(bCosθ, bSinθ) respectively.

Now by using the distance formula

040523 1538 TOPIC5TRIGO39

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SINE RULE

Consider the triangle ABC below

040523 1538 TOPIC5TRIGO41

From the figure above,

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Note that this rule can be started as “In any triangle the side are proportional to the Sines of the opposite angles”

The Sine and Cosine Rules in Solving Problems on Triangles

Apply the sine and cosine rules in solving problems on triangles

Example 12

Find the unknown side and angle in a triangle ABC given that

a= 7.5cm

c= 8.6cm and C= 80°

040523 1538 TOPIC5TRIGO43

040523 1538 TOPIC5TRIGO44

Find the unknown sides and angle in a triangle ABC in which a= 22.2cmB= 86°and A= 26°

Solution

By sine rule

Sin A= sin B= Sin C

040523 1538 TOPIC5TRIGO45

Example 13

Find unknown sides and angles in triangle ABC

Where a=3cm, c= 4cm and B= 30°

Solution

By cosine rule,

040523 1538 TOPIC5TRIGO46

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Example 14

Find the unknown angles in the following triangle

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Exercise 3

1. Given thata=11cm, b=14cm and c=21cm, Find the Largest angle of ΔABC

2. If ABCD is a parallelogram whose sides are 12cm and 16cm what is the length of the diagonal AC if angle B=119°?

3. A and B are two ports on a straight Coast line such that B is 53km east of A. A ship starting from A sails 40km to a point C in a direction E65°N. Find:

  • The distance a of the ship from B
  • The distance of the ship from the

Compound Angles

The Compound of Angle Formulae or Sine, Cosine and Tangent in Solving Trigonometric Problems

Apply the compound of angle formulae or sine, cosine and tangent in solving trigonometric problems

The aim is to express Sin (α±β) and Cos (α±β) in terms of Sinα, Sinβ, Cosαand Cosβ

Consider the following diagram:

040523 1538 TOPIC5TRIGO52

From the figure above <BAD=αand <ABC=βthus<BCD=α+β

From ΔBCD

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For Cos(α±β) Consider the following unit circle with points P and Q on it such that OP,makes angleα with positive x-axis and OQ makes angle βwith positive x-axes.

040523 1538 TOPIC5TRIGO54

From the figure above the distance d is given by

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In general

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Example 15

1. Withoutusing tables find the value of each of the following:

  • Sin 75°
  • Cos105

Solution:

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Example 16

Find:

  1. Sin150°
  2. Cos 15°

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Exercise 4 (Trigonometry)

1. Without using tables, find:

  • Sin15°
  • Cos 120°

2. Find Sin 225° from (180°+45°)

3. Verify that

  • Sin90° = 1 by using the fact that 90°=45°+45°
  • Cos90°=0 by using the fact that 90°=30°+60°

4. Express each of the following in terms of sine, cosine and tangent of acute angles.

  1. Sin107°
  2. Cos300°

5. By using the formula for Sin (A-B), show that Sin (90°-C)=Cos C

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